MJay

256 - DP - Paint House 본문

Programming/LeetCode

256 - DP - Paint House

MJSon 2019. 10. 21. 10:32

Given a string s and a string t, check if s is subsequence of t.

You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).

A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not).

Example 1:

s = "abc", t = "ahbgdc"

Return true.

Example 2:

s = "axc", t = "ahbgdc"

Return false.

Follow up:

If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?

Credits:

Special thanks to @pbrother for adding this problem and creating all test cases.



 

ㄱㅐ수가 k 개이면 for 문에서 또 k 만큼 해야하니 O(n) -> O(kn)이다.

 

예시로 이렇게 들어서 하면 괜찮겠다. 

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